(09.01 MC) Two quadratic functions are shown. Function 2: Function 1: f(x) = 2×2 – 8x + 1 |x g(x)

Question

(09.01 MC)
Two quadratic functions are shown.
Function 2:
Function 1:
f(x) = 2×2 – 8x + 1
|x
g(x)
1
17
Which function has the least minimum value and what are its coordinates? (5 points)
Function 1 has the least minimum value and its coordinates are (0, 1).
Function 1 has the least minimum value and its coordinates are (2. – 7).
Function 2 has the least minimum value and its coordinates are (0,2).
Function 2 has the least minimum value and its coordinates are (-1.-3).

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Liliana 2 months 2021-12-02T02:35:15+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-12-02T02:36:17+00:00

    Answer:

    function one has the least minimum value
    , coordinates are (2.-7)

    Step-by-step explanation:

    0
    2021-12-02T02:37:04+00:00

    Answer:

    Function 1 has the least minimum value and its coordinates are (2. – 7).

    Step-by-step explanation:

    The first function is

    f(x)=2x^{2} -8x+1

    The second function is

    x   g(x)

    -2    2

    -1    -3

    0     2

    1     17

    The vertex has coordinates of V(h,k), where h=-\frac{b}{2a} and k=f(h).

    Let’s find the vertex for the first function where a=2 and b=-8.

    h=-\frac{-8}{2(2)}=2

    k=f(2)=2(2)^{2} -8(2)+1=8-16+1=-8+1=-7

    Therefore, the vertex of the first function is at (2,-7).

    Now, the minimum value of the second function can be deducted from its table, which is (-1,-3).

    Therefore, f(x) has -7 as minimum value and g(x) has -3 as minimum vale.

    So, the right answer is B, because -7 is less than -3.

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45:7+7-4:2-5:5*4+35:2 =? ( )