1.28. Let {p1, p2,…,pr} be a set of prime numbers, and let N = p1p2 ··· pr + 1. Prove that N is divisible by some prime not in the origi

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1.28. Let {p1, p2,…,pr} be a set of prime numbers, and let N = p1p2 ··· pr + 1. Prove that N is divisible by some prime not in the original set.Hoffstein, Jeffrey. An Introduction to Mathematical Cryptography (Undergraduate Texts in Mathematics) (p. 54). Springer New York. Kindle Edition.

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Margaret 2 weeks 2022-01-03T13:59:38+00:00 1 Answer 0 views 0

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    2022-01-03T14:00:38+00:00

    Answer:

    Step-by-step explanation:

    Let N = {P1, P2, ….Pr +1}

    This implies that if N is a prime, using mod1, then N is not divisible by P since we are aware that for every integer, it must be easy to factor them into product of prime. so we say, if N is not prime, there is a high probability that it will still be divisible by some prime and not all primes, as such the p value is not among the element listed in the bracket.

    In the  N = {P1, P2, ….Pr +1}, they are all exact number that are divisible by some prime but not in among the elements listed in he bracket, most possible there are infinitely many prime numbers.

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45:7+7-4:2-5:5*4+35:2 =? ( )