x^2-6x+9=0 solve by completing the square

Question

x^2-6x+9=0 solve by completing the square

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Peyton 3 weeks 2022-01-06T03:32:33+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-06T03:34:04+00:00

    Use the quadratic formula to find the solutions.

    b
    ±

    b
    2

    4
    (
    a
    c
    )
    2
    a

    b
    ±
    b
    2

    4
    (
    a
    c
    )
    2
    a
    Substitute the values
    a
    =
    1
    a
    =
    1
    ,
    b
    =
    0
    b
    =
    0
    , and
    c
    =

    9
    c
    =

    9
    into the quadratic formula and solve for
    x
    x
    .
    0
    ±

    0
    2

    4

    (
    1


    9
    )
    2

    1
    0
    ±
    0
    2

    4

    (
    1


    9
    )
    2

    1
    Simplify.
    Tap for more steps…
    x
    =
    ±
    3
    x
    =
    ±
    3
    The final answer is the combination of both solutions.
    x
    =
    3
    ,

    3

    0
    2022-01-06T03:34:26+00:00

    Answer:

    x=3

    Step-by-step explanation:

    Step 1: Subtract 9 from both sides.

    x2−6x+9−9=0−9

    x2−6x=−9

    Step 2: The coefficient of -6x is -6. Let b=-6.

    Then we need to add (b/2)^2=9 to both sides to complete the square.

    Add 9 to both sides.

    x2−6x+9=−9+9

    x2−6x+9=0

    Step 3: Factor left side.

    (x−3)2=0

    Step 4: Take square root.

    x−3=±√0

    Step 5: Add 3 to both sides.

    x−3+3=3±√0

    x=3±√0

    x=3+0 or x=3−0

    x=3

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