x 4 6 9 11 15 P(x) 0.20 0.34 0.15 0.22 0.09 This table shows a probability distribution for a discrete random variab

Question

x 4 6 9 11 15
P(x) 0.20 0.34 0.15 0.22 0.09
This table shows a probability
distribution for a discrete random
variable. What is the mean of this
discrete random variable?
O9
O 0.2
0 1
O 7.96

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Kinsley 2 weeks 2021-09-27T03:48:54+00:00 1 Answer 0

Answers ( )

    0
    2021-09-27T03:50:50+00:00

    The mean of this  discrete random variable is 7.96

    Solution:

    Given that,

    x         4       6          9         11        15

    P(x)   0.20   0.34     0.15    0.22     0.09

    Mean is given as:

    \mu_{x}=\sum[x \times P(x)]

    Therefore,

    \mu_{x} = (4 \times 0.20) + (6 \times 0.34 ) + (9 \times 0.15 ) + (11 \times 0.22 ) + (15 \times 0.09)\\\\Simplify\\\\\mu_{x} = 0.8 + 2.04 + 1.35 + 2.42 + 1.35\\\\\mu_{x} = 7.96

    Thus, mean of this  discrete random variable is 7.96

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45:7+7-4:2-5:5*4+35:2 =? ( )