4 green marbles, 5 red marbles, and 2 yellow marbles are placed into a bag. One marble is chosen and replaced into the bag. A second marble

Question

4 green marbles, 5 red marbles, and 2 yellow marbles are placed into a bag. One marble is chosen and replaced into the bag. A second marble is chosen. What is the probability a red marble and then a yellow marble are chosen? Write answer in simplest fraction form,

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Arya 2 weeks 2021-11-16T06:56:47+00:00 1 Answer 0 views 0

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    2021-11-16T06:57:51+00:00

    Answer:

    The probability is 10/121

    Step-by-step explanation:

    In this question, we are tasked with calculating probability.

    The probability to be calculated is that we have an ordered selection of picking a red marble after which we pick a yellow marble.

    Firstly let us know the total number of marbles we have. That will be 4 + 5 + 2 = 11 marbles

    Probability of picking a red marble will be 5/11 while the probability of picking a yellow marble will be 2/11

    Now, the probability of picking a red marble before a yellow marble will be mathematically equal to; P(r) * P(y) = 5/11 * 2/11 = 10/121

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45:7+7-4:2-5:5*4+35:2 =? ( )