5.5.4 1 If y varies inversely with the square of x, and y = 13 when x = 2, find y when x = 0.5.

Question

5.5.4
1
If y varies inversely with the square of x, and y = 13 when x = 2, find y when x = 0.5.

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Camila 2 weeks 2021-09-09T15:55:12+00:00 1 Answer 0

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    2021-09-09T15:57:09+00:00

    Answer:

    y = 208

    Step-by-step explanation:

    We need to solve this problem, we need to interpret the question

    y varies inversely means 1/

    y varies inversely with the square of x

    That’s y varies /x^2

    To equate it, we need to add a constant K

    y = K * 1/x^2

    y = K/x^2

    As we’ve been provided with some information

    y = 13

    x = 2

    Inserting into

    y = K/x^2

    13 = K/2^2

    13 = K/4

    K = 13 * 4

    K = 52

    Our constant is 52

    Provided on the another information we are given to find y, x = 0.25

    Using the same formula

    y = K/x^2

    K = 52

    x = 0.25

    y = 52/0.25

    y = 208

    The new value of y is 208 when x = 0.25

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