9. A person stands at the window of a building so that his eyes are 12.6 m above the level ground. An object is on the ground 58

Question

9. A person stands at the window of a building so that his eyes are 12.6 m above the level ground. An

object is on the ground 58.5 m away from the building on a line directly beneath the person. Compute

the angle of depression of the person’s line of sight to the object on the ground.

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Harper 1 month 2021-10-15T01:39:19+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-15T01:41:04+00:00

    Answer:

    \theta = 12.16^0.

    Step-by-step explanation:

    Given,

    Height = 12.6 m

    Object distance from the person = 58.5 m

    Angle of depression

    tan \theta = \dfrac{P}{B}

    tan \theta = \dfrac{12.6}{58.5}

    tan \theta = 0.2154

    \theta = 12.16^0

    Hence, angle of depression is equal to \theta = 12.16^0.

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