The question has some details missing or incomplete. here is the complete part of the question ; 18% of all students at West Colon High School play baseball and 32% play soccer. The probability that a student plays baseball given that the student plays soccer is 22%.

a) Calculate the probability that a student plays both baseball and soccer.

Step-by-step explanation:

Let X = all students at West Colon High School play baseball

Y = all students at West Colon High School play soccer

Given P(X) = 0.18. P(Y) = 0.32, P(X|Y) = 0.22

but P(X|Y) = P(XnY) / P(B)

Therefore, P(XnY) = P(X|Y) x P(B)

therefore = the probability that a student plays both baseball and soccer P(XnY) = 0.22 x 0.32 = 0.0704

## Answers ( )

Answer:The question has some details missing or incomplete. here is the complete part of the question ; 18% of all students at West Colon High School play baseball and 32% play soccer. The probability that a student plays baseball given that the student plays soccer is 22%.

a) Calculate the probability that a student plays both baseball and soccer.

Step-by-step explanation:Let X = all students at West Colon High School play baseball

Y = all students at West Colon High School play soccer

the probability that a student plays both baseball and soccer P(XnY) = 0.22 x 0.32 = 0.0704