A(1,1), B(3,6) and c(5,1) are the vertices of a triangle. Show that |AB|=|BC| Please help have no clue

Question

A(1,1), B(3,6) and c(5,1) are the vertices of a triangle. Show that |AB|=|BC|

Please help have no clue

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Eden 1 week 2021-09-09T03:08:37+00:00 2 Answers 0

Answers ( )

    0
    2021-09-09T03:09:51+00:00

    Answer:

    see explanation

    Step-by-step explanation:

    Calculate both AB and BC using the distance formula

    d = √ (x₂ – x₁ )² + (y₂ – y₁ )²

    with (x₁, y₁ ) = A(1, 1) and (x₂, y₂ ) = B(3, 6)

    AB = \sqrt{(3-1)^2+(6-1)^2}

         = \sqrt{2^2+5^2}

         = \sqrt{4+25} = \sqrt{29}

    Repeat the process with

    (x₁, y₁ ) = B(3, 6) and (x₂, y₂ ) = C(5, 1)

    BC = \sqrt{(5-3)^2+(1-6)^2}

         = \sqrt{2^2+(-5)^2}

         = \sqrt{4+25} = \sqrt{29}

    Thus |AB | = |BC | = \sqrt{29}

    0
    2021-09-09T03:10:32+00:00

    Answer:

    explained

    Step-by-step explanation:

    Calculate both AB and BC using the distance formula

    d = √ (x₂ – x₁ )² + (y₂ – y₁ )²

    with (x₁, y₁ ) = A(1, 1) and (x₂, y₂ ) = B(3, 6)

    AB =  

        =  

        =  =  

    Repeat the process with

    (x₁, y₁ ) = B(3, 6) and (x₂, y₂ ) = C(5, 1)

    BC =  

        =  

        =  =  

    Thus |AB | = |BC | =

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