a.b^2=12 b.c^2=16 c.a^2=9 a.b.c=?

Question

a.b^2=12
b.c^2=16
c.a^2=9
a.b.c=?

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Emery 2 months 2021-10-07T17:44:24+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-07T17:46:05+00:00

    Answer:

    12

    Step-by-step explanation:

    (a.b^2)×(b.c^2)×c.a^2 = 12×16×9 = 1 728

    then

    a^3×b^3×c^3 = 1728

    then

    (abc)^3 = 1728

    then

    abc = 12

    0
    2021-10-07T17:46:21+00:00

    Answer:

    Step-by-step explanation:

    (a.b²)*(b.c²)*(c.a²) = 12 * 16 * 9

    a³*b³*c³= 4*3 * 4*4 *3*3

    (abc)³ = 4³ * 3³

    (abc)³ = (4*3)³

    (abc)³ = (12)³

    Therefore,

    abc = 12

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45:7+7-4:2-5:5*4+35:2 =? ( )