A bag contains 4 blue marbles, 4 red marbles and 4 green marbles. What’s the probability of drawing 2 green marbles WITH replacement? ** R

Question

A bag contains 4 blue marbles, 4 red marbles and 4 green marbles. What’s the probability of drawing 2 green marbles WITH replacement? ** Remember P(A and B) = P(A) x P(B)

Question 5 options:

a.1/9

b.1/6

c.1/4

d.1/2

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Alice 2 weeks 2022-01-08T04:37:56+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-01-08T04:39:35+00:00

    Answer:

    A

    Step-by-step explanation:

    If we look at the problem given, we notice there are 12 marbles in total and 4 green. We want to find the probability of drawing green with replacement.

    With that said, the work would be as shown:

    P(A and B) = P(A) * P(B)\\P(A) = \frac{4}{12} \\P(B) = \frac{4}{12} \\\frac{4}{12} * \frac{4}{12} = \frac{16}{144} \\ \frac{16}{144} / 16 = \frac{1}{9}

    I’m happy to help with any other questions you might have in the future and I will do my best to provide the brainliest answers 🙂

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45:7+7-4:2-5:5*4+35:2 =? ( )