A bag contains 4 red marbles, 3 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the probability, to the n

Question

A bag contains 4 red marbles, 3 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be red?

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Madelyn 2 months 2021-10-15T19:05:35+00:00 1 Answer 0 views 0

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    2021-10-15T19:07:24+00:00

    Answer:

    ≈19.7%

    Step-by-step explanation:

    To solve this, we first need to find the probability of drawing one red marble. You can do this by adding up all of the marbles and deriving a fraction of red marbles which would get you:

    Probability of red= \frac{4}{9}

    To find the probability of drawing red 2 times, you will simply need to multiply:

    \frac{4}{9} ×\frac{4}{9}= \frac{16}{81}

    To convert this to a percent, you can simply divide…

    16÷81≈0.197

    …And then multiply by 100.

    0.197×100= 19.7%

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