A box contains 4 red markers and 2 blue markers a marker is selected at random and it’s color is noted. If it is red it is replaced; otherwi

Question

A box contains 4 red markers and 2 blue markers a marker is selected at random and it’s color is noted. If it is red it is replaced; otherwise it is not. A second marker is selected and it’s color is noted. If the second is blue, find the probability that the first was blue?

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Autumn 3 weeks 2021-11-10T18:10:32+00:00 1 Answer 0 views 0

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    2021-11-10T18:11:42+00:00

    Answer:

    The probability of first one to be  blue is \frac{1}{3}.

    Step-by-step explanation:

    In the given box, there are 4 red markers and 2 blue markers.

    The given scenario will not affect the required probability as the selection of the second one is a case of future.

    We need to find the probability of the first marker is blue.

    The probability is \frac{blue markers}{total markers} = \frac{2}{6} = \frac{1}{3}.

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45:7+7-4:2-5:5*4+35:2 =? ( )