A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower th

Question

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.

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Adeline 2 weeks 2021-09-09T02:19:36+00:00 2 Answers 0

Answers ( )

    0
    2021-09-09T02:21:29+00:00

    Step-by-step explanation:

    1. Let our Motorcycle variable=X

    We know that it travels twice the speed so it’s 2M

    We also know that the car is 30 mph slower

    so our equation is : 2x-30

    2. As we’re finding speed we will be using the equation: speed=distance X time

    So: it also says that we need to find the speed after 2 hours

    So by adding in 2 this will be: 2(2x-30)

    3. The question also stated that it’ll be 20mph ahead (car)

    So the equation which we can work out now is

    2(2x-30)= 2x+20

    4. We can find X

    2(2x-30)=2x+20 (Multiply out brackets)

    4x-60=2M+20 (Subtract 2M as it’s less than 4M)

    2x-60=20 (Add 60 as we need to find M)

    2x=80 (Divide by 2 as 80 is multiple of 2)

    x=40 mph

    So, x=40 mph

    5. Find the speed of the car and motorcycle

    Motorcycle: 40 mph

    Car: By using 2x30

    Substitute the 40 with the 2

    So, 2*40 is 180

    18030 = 50 mph

    Hence, the car is 50 mph and the motorcycle speed is 40 mph

    Hope this helps!!!

    Have a nice day :)

    0
    2021-09-09T02:21:34+00:00

    Answer:

    30 i am not sure if it is correct

    Step-by-step explanation:

    30-2=10

    20+10=30

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