A circle has the equation (x−13)2+(y−1)2=4. A: What is the center of the circle? B: What is the radius of the circle?

Question

A circle has the equation (x−13)2+(y−1)2=4.
A: What is the center of the circle?
B: What is the radius of the circle?

Select two answers: one for question A, and one for question B.

A: (13,1)

B: 4

A: (−13,−1)

A: (−13,1)

A: (13,−1)

B: 2

B: 2–√

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Julia 6 days 2021-10-12T20:25:57+00:00 1 Answer 0

Answers ( )

  1. Emma
    0
    2021-10-12T20:27:24+00:00

    An equation of circle has form

    (x-x_0)^2+(y-y_0)^2=r^2 \\ where\: x_0\: and\: y_0\: are\: the\: center

    So, the center is (13;1)

    Now we need to find a radius

    Let’s create an equation

     {r}^{2}  = 4 \\ r =  \sqrt{4}  \\ r = 2

    So radius is 2

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