a cup was filled at a constant rate. it started empty. after 2 seconds, it held 70 cm cubes of water. the radius is 4 and te height is 7. fi

Question

a cup was filled at a constant rate. it started empty. after 2 seconds, it held 70 cm cubes of water. the radius is 4 and te height is 7. find the percent of the cup that is filled with water after 3 seconds. this is a cone

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Mary 2 weeks 2021-09-09T06:38:37+00:00 1 Answer 0

Answers ( )

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    2021-09-09T06:40:03+00:00

    Answer:

    89.51%

    Step-by-step explanation:

    Assuming given units are in cm

    Tge rate of filling the cup is 70/2= 35 cm3/s

    Volume of the cup is \pi r^{2}\frac {h}{3} and replacing r with 4 cm and h with 7 cm then the volume is equivalent to

    \pi*4^{2}*\frac {7}{3}= 117.3 cm^{3}

    Volume filled after 3 seconds will be 3*35=105 cm3

    Percentage filled is \frac {105}{117.3}\times 100\approx 89.51

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45:7+7-4:2-5:5*4+35:2 =? ( )