A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a single card is

Question

A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number

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Genesis 1 week 2021-09-14T23:07:01+00:00 1 Answer 0

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    2021-09-14T23:08:18+00:00

    Answer: 1/52

    Step-by-step explanation:

    A deck of cards contains 52 cards

    Red cards are numbered 1,2,3

    Blue cards are numbered 1,2,3,4,5,6

    Green cards are numbered 1,2

    Number of Red card = 3

    Number of blue card = 6

    Number of Green card = 2

    Let Pr(R) = Probability of picking a Red card

    Let Pr(B) = probability of picking a blue card

    Let Pr(G) = probability of picking a green card

    Let Pr(RE) = Probability of picking a red even card

    Let Pr(RO) = probability of picking a red odd card

    Let Pr(BE) =probability of picking a blue even card

    Let Pr(BO) = probability of picking a blue odd card

    Let Pr(GE) = probability of picking a green even card

    Let Pr(GO) = probability of picking a green odd card

    Pr(R) = 3/52

    Since we have 3 red cards,

    Pr(RE) = 1/3

    Pr(RO) =2/3

    Pr(B) = 6/52

    = 3/26

    Since we have 6 blue cards ,

    Pr(BE) = 3/6

    = 1/2

    Pr(BO) = 3/6

    = 1/2

    Pr (G) = 2/52

    = 1/26

    Since we have 2 green cards,

    Pr(GE) = 1/2

    Pr(GO) = 1/2

    The probability of picking a Green card and an odd green card is

    Pr(G) n pr(GO)

    1/26 * 1/2

    = 1/52

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