## A golfer hits a ball from a starting elevation of 6 feet with a velocity of 70 feet per second down to a green with an elevation of −3 feet.

Question

A golfer hits a ball from a starting elevation of 6 feet with a velocity of 70 feet per second down to a green with an elevation of −3 feet. The number of seconds t it takes the ball to hit the green can be represented by the equation −16t2 + 70t + 6 = −3. How long does it take the ball to land on the green? It takes the ball seconds to land on the green.

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2 months 2021-10-03T17:02:12+00:00 1 Answer 0 views 0

## Answers ( )

1. Answer:

The time it takes the ball to land on green is 4.4175 seconds

Step-by-step explanation:

Given

Equation for number of seconds it take to hit the green: −16t² + 70t + 6 = −3

Required

The value of t.

The interpretation of this question is that, we should solve for t in the above equation.

-16t² + 70t + 6 = −3

Collect like terms

-16t² + 70t + 6 – 3 = 0

-16t² + 70t + 3 = 0

Multiply through by -1

-1(-16t² + 70t + 3) = -1 * 0

16t² – 70t – 3 = 0

Solving using quadratic formula.

Where a = 16, b = -70, c = -3

t = (-(-70) ± √(-70² – 4 * 16 * -3))/(2 * 16)

t = (70 ± √(4900 + 192))/32

or

or

But t can’t be negative.

So, t = 4.4175

The time it takes the ball to land on green is 4.4175 seconds