A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Btu/h. Evaluat

Question

A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Btu/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours

in progress 0
Sarah 1 month 2021-12-27T08:59:15+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-12-27T09:01:00+00:00

    Answer:

    $720

    Step-by-step explanation:

    Coefficient of performance of a refrigerator (COP) =\frac{desired ouput}{Required inpu}

    desired out i.e energy removed = 600Bth/hr

    Required input=?

    2.4=\frac{600}{required inpu}

    required input=\frac{600}{24}=25Btu/hr

    cost of electricity per hour = $0.08

    cost of electricity for 360 hours =$0.08×360=$28.8

    for an input of 25Btu/hr and 360 hours

    ∴cost of electricity in month =$28.8×25=$720

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )