## A hyperbola centered at the origin has vertices at (0,±\sqrt(54) and foci at (0,±\sqrt(89) Write the equation of this hyperbola

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## Answers ( )

answer:The equation has the form y2a2−x2b2=1 y 2 a 2 − x 2 b 2 = 1 , so the transverse axis lies on the y-axis. The hyperbola is centered at the origin, so the vertices serve as the y-intercepts of the graph. To find the vertices, set x=0 x = 0 , and solve for y y .