## A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find the probabil

Question

A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find the probability that the marble is blue or even-numbered.

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3 weeks 2021-09-27T00:45:31+00:00 1 Answer 0

Therefore the probability that the marble is blue or even numbered is Step-by-step explanation:

Probability: The ratio of favorable outcomes to the total outcomes.

It is denoted by P. Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)  The probability of getting a even marble  is P(B)  The probability of getting a even numbered blue marble P(A∩B) P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)  Therefore the probability that the marble is blue or even numbered is 