## a large number of voltages show a mean of 118.5v and a population standard deviation of 1.20v. determine the percentage of data that falls b

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## Answers ( )

Answer:Step-by-step explanation:Hello!

X: voltage, it has a mean of μ= 118.5V and a standard deviation of σ= 1.20V.

Assuming the variable has a normal distribution, I’ll use the standard normal distribution to calculate the probability that the voltage is between 116 and 120 volts.

P(116≤X≤120) = P(X≤120) – P(X≤116)

Using Z= (X – μ)/σ you now standardize the voltage values and get the cumulative probabilities from the tables of Z.

P(Z≤(120-118.5)/1.20) – P(Z≤(116-118.5)/1.20)

P(Z≤1.25) – P(Z≤-2.08)= 0.89435 – 0.01876= 0.87559

87.559% of the data will be between 116 and 120 volts.

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