A line is perpendicular to y = 4x – 2 and intersects the point (4, -11). What is the equation of this perpendicular line?<

Question

A line is perpendicular to y = 4x – 2
and intersects the point (4, -11).
What is the equation of this
perpendicular line?
y = – 3x + [?]
Hint: Use the Point-Slope Form: y – y1 = m(x – X1)
Then write the equation in slope-intercept form.

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Rylee 1 week 2021-09-14T23:16:44+00:00 1 Answer 0

Answers ( )

    0
    2021-09-14T23:18:21+00:00

    Answer:

    y=-\frac{1}{4}x-10

    Step-by-step explanation:

    If a line is perpendicular to a line that has slope m, then the slope of the line is -1 / m.

    in this case, y=4x-2

    m=4 by comparing with y=mx+c

    the slope of the perpendicular line is

    m=-\frac{1}{4}

    use the point-slope form: y-y_{0}=m(x-x_{0} )

    the equation of the perpendicular line is

    y+11=-\frac{1}{4}(x-4)=-\frac{1}{4}x+1\\y=-\frac{1}{4}x+1-11=-\frac{1}{4}x-10

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45:7+7-4:2-5:5*4+35:2 =? ( )