A line passes through the points (1. 4) and (3.-4). Which is the equation of the line? O y=-4x+8 y=-2x + 8 0 – – 4x

Question

A line passes through the points (1. 4) and (3.-4). Which is the equation of the line?
O
y=-4x+8
y=-2x + 8
0 – – 4x + 2
o y= 2x+2

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Elliana 1 week 2022-01-10T20:14:42+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-01-10T20:15:53+00:00

    Slope-intercept form:  y = mx + b

    (m is the slope, b is the y-intercept or the y value when x = 0 –> (0, y) or the point where the line crosses through the y-axis)

    To find the slope(m), use the slope formula:

    m=\frac{y_2-y_1}{x_2-x_1}       And plug in the two points on the line

    (1, 4) = (x₁, y₁)

    (3, -4) = (x₂, y₂)

    m=\frac{y_2-y_1}{x_2-x_1}

    m=\frac{-4-4}{3-1}

    m=\frac{-8}{2}    Simplify the fraction

    m = -4  

    Now that you know the slope, substitute/plug it into the equation.

    y = mx + b

    y = -4x + b   To find b, plug in either of the points into the equation, it doesn’t matter which, the isolate/get the variable “b” by itself. I will use (1, 4)

    4 = -4(1) + b     Add 4 on both sides to get “b” by itself

    4 + 4 = -4 + 4 + b

    8 = b

    y = -4x + 8     Your answer is the 1st option

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