A liner is parallel to y = 3x-13 and intersects the point (1,-2) . What is the equation of this parallel line ?

Question

A liner is parallel to y = 3x-13 and intersects the point (1,-2) . What is the equation of this parallel line ?

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Ella 6 days 2022-01-07T18:23:43+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-07T18:25:03+00:00

    Answer:

    y=3x-5

    Step-by-step explanation:

    Use the point slope formula:

    y-y_{1} =m(x-x_{1})

    Slope (m)

    We know the slope is 3, because parallel lines have the same slopes.

    y = 3x-13

    This is in y=mx+b form, where m is the slope and b is the y intercept. We know that 3 is the slope because it is being multiplied by x.

    Point (x1, y1)

    Points are written like so: (x, y)

    So, for (1, -2), 1 is our x1, and -2 is our y1.

    Now we know the m is 3, x1 is 1 and y1 is -2, so we can substitute them in

    y-y_{1} =m(x-x_{1})

    y- -2=3(x-1)

    y+2=3(x-1)

    y+2= 3*x + 3*-1           Distribute the 3

    y+2=3x-3

    y+2-2=3x-3-3          Subtract 2 from both sides

    y=3x-5

    0
    2022-01-07T18:25:23+00:00

    Answer:

    y = 3x – 5

    Step-by-step explanation:

    If a line is parallel to another line, the slopes are the same. This means that the equation we will find is y = 3x + b, where b is real.

    Plug in point

    -2 = 3(1) + b

    Simplify

    -2 = 3 + b

    Simplify

    -5 = b

    y = 3x -5

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