A man has a son and a daughter. The son is 3 years older than the daughter. In one year the man will be six times as old as the daughter is

Question

A man has a son and a daughter. The son is 3 years older than the daughter. In one year the man will be six times as old as the daughter is now. In ten years the man will be 14 years older than the combined ages of his children at that time. What is the man’s present age?

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Piper 2 months 2021-10-05T12:41:28+00:00 1 Answer 0 views 0

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    2021-10-05T12:43:00+00:00

    Answer:

    41 years old

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45:7+7-4:2-5:5*4+35:2 =? ( )