A parabola has a vertex at (-3,2). Where is the axis of symmetry?

Question

A parabola has a vertex at (-3,2). Where is the axis of symmetry?

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Iris 2 months 2021-10-07T02:12:58+00:00 2 Answers 0 views 0

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    0
    2021-10-07T02:14:16+00:00

    Answer:

    The axis of symmetry of the parabola with a vertex at (-3, 2) is at

    x = -1/2

    Step-by-step explanation:

    Given a quadratic function (parabola) of the form:

    y = ax² + bx + c

    The axis of symmetry of the function is a vertical line that divides the parabola into two congruent halves. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

    This is given as x = -b/2a

    We are given a parabola with vertex at (-3, 2). The quadratic function corresponding to this is

    y = (x -(-3))(x – 2)

    = (x + 3)(x – 2)

    = x² – 2x + 3x – 6

    y = x² + x – 6

    Here, a = 1, b = 1, and c = -6

    The axis of symmetry is at

    x = -b/2a

    = -1/2(1)

    = -1/2

    0
    2021-10-07T02:14:36+00:00

    Answer:

    x=-3

    Step-by-step explanation:

    If a parabola has a vertex at (h,k), the axis of symmetry is at the point, x=h.

    That is, the x-coordinate of the vertex of the given parabola is the axis of symmetry.

    Therefore, for a parabola with vertex (-3,2), the axis of symmetry is at x=-3

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