A pizza parlor has a special on a three-topping pizza. How many different special pizzas can be ordered if the parlor has 8 toppings to choo

Question

A pizza parlor has a special on a three-topping pizza. How many different special pizzas can be ordered if the parlor has 8 toppings to choose from?

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Eden 1 week 2021-09-15T23:55:35+00:00 2 Answers 0

Answers ( )

    0
    2021-09-15T23:57:06+00:00

    Answer:

    We assume the three toppings must be different.

    Explanation:

    Cheese :  

    3

    choices

    Toppings :  

    8

    choices for the first,  

    7

    for the second and  

    6

    for the third, a total of  

    8

    ×

    7

    ×

    6

    =

    336

    , IF the order of toppings were important — which it isn’t. This number is called the number of permutations .

    Three things can be ordered in 6 ways (try this), so in the 336 permutations, there are groups of 6 that amount to the same combination :

    123=132=213=231=312=321, etc.

    So we have to divide the number of permutations by the number of orders to reach the number of combinations:

    There are thus 336 : 6 = 56 possibilities for the toppings.

    Since we need cheese AND toppings we multiply:

    Number of different pizzas: 3 x 56 = 168.

    Calculator : if you have the nCr function the answer would be:

    3 x 8 nCr 3 = 168

    Step-by-step explanation:

    0
    2021-09-15T23:57:13+00:00

    I think the answer is 24

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45:7+7-4:2-5:5*4+35:2 =? ( )