A rectangle has a perimeter of 76. if the width is five more than twice the length find the width and length

Question

A rectangle has a perimeter of 76. if the width is five more than twice the length find the width and length

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Nevaeh 2 weeks 2021-09-10T18:53:54+00:00 1 Answer 0

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    2021-09-10T18:55:40+00:00

    Answer: The width is 27, while the length is 11.

    Step-by-step explanation: If the width is five more than twice the length, and the length is given as L, then the width can be expressed as

    5 + 2 x L

    = 5 + 2L

    If the perimeter is 76, and the perimeter of a rectangle is given as

    Perimeter = 2(L + W), then

    Perimeter = 2(L + 5 + 2L)

    Perimeter = 2(3L + 5)

    76 = 6L + 10

    Subtract 10 from both sides of the equation

    66 = 6L

    Divide both sides of the equation by 6

    L = 11

    Having calculated the value of L, the width can now be computed as follows

    W = 5 + 2L

    W = 5 + 2(11)

    W = 5 + 22

    W = 27

    Hence the dimensions are, Length = 11 and Width = 27.

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