A rectangle has an area of x^2-8x-48. If the width is (x+4) find the length.

Question

A rectangle has an area of x^2-8x-48. If the width is (x+4) find the length.

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Kennedy 3 weeks 2021-09-07T17:06:54+00:00 1 Answer 0

Answers ( )

    0
    2021-09-07T17:08:04+00:00

    Answer:x-12

    Step-by-step explanation:

    Area=x^2-8x-48

    Width=x+4

    length=area/width

    length=(x^2-8x-48)/(x+4)

    length=((x+4)(x-12))/(x+4)

    length=x-12

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45:7+7-4:2-5:5*4+35:2 =? ( )