A sequence is defined by the recursive function f(n + 1) = 1/3f(n). If f(3) = 9 , what is f(1) Question A sequence is defined by the recursive function f(n + 1) = 1/3f(n). If f(3) = 9 , what is f(1) in progress 0 Math Alice 2 weeks 2021-09-09T17:53:49+00:00 2021-09-09T17:53:49+00:00 2 Answers 0

## Answers ( )

Answer: D on edge 2020

Step-by-step explanation:

ðŸ™‚

Answer:f(1) = 81

Step-by-step explanation:given is f(n + 1) = 1/3f(n)

f(3) = 9

ayou need to find f(0) before you can answer what is f(1).

Just start by applying for…

n=0

f(0+1) = 1/3 * f(0)

f(1) = 1/3 * f(0)

n=1

f(1+1) = 1/3 * 1/3*f(0)

f(2) = 1/9 * f(0)

n=2

f(2+1) = 1/3 * 1/9* f(0)

f(3) = 1/27 * f(0)

But it is given that f(3) = 9 so substitute this in the line above to calculate the value of f(0)….

9 = 1/27 * f(0)

Multiply left and right of the = sing by 27 gives

f(0) = 27 * 9

f(0) = 243

We already know this next line because we started with n=0

f(1) = 1/3 * f(0)

Substitute f(0) = 243 in the line above to finally calculate the value of f(1).

f(1) = 1/3 * 243

f(1) = 81