A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12. In simpl

Question

A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12. In simplest form, what is the probability of landing on orange?

in progress 0
Julia 2 weeks 2022-01-12T08:55:37+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-01-12T08:57:29+00:00

    Answer:

    Step-by-step explanation:

    P(landing on orange)=1 – [2/3 + 1/12 + 1/12]

    =1-[\frac{2}{3}+\frac{2}{12}]\\\\=1-[\frac{2}{3}+\frac{1}{6}]\\\\=1-[\frac{2*2}{3*2}+\frac{1}{6}]\\\\=1-[\frac{4}{6}+\frac{1}{6}]\\\\=1-[\frac{4+1}{6}]\\\\=1-\frac{5}{6}\\\\=\frac{6}{6}-\frac{5}{6}\\\\=\frac{1}{6}

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )