## A tank contains 100 kg of salt and 1000 L of water. A solution of a concentration 0.05 kg of salt per liter enters a tank at the rate 10 L/m

Question

A tank contains 100 kg of salt and 1000 L of water. A solution of a concentration 0.05 kg of salt per liter enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the same rate.

(a) What is the concentration of our solution in the tank initially?

concentration = (kg/L)

(b) Find the amount of salt in the tank after 1 hours.

amount = (kg)

(c) Find the concentration of salt in the solution in the tank as time approaches infinity.

concentration = (kg/L)

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2022-01-07T15:22:42+00:00
2022-01-07T15:22:42+00:00 1 Answer
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## Answers ( )

Answer:Step-by-step explanation:Initial Quantity of salt Q(0) = 100 kg

Capacity of tank = 1000 L

Inflow of liquid = 10 l /minute and outflow = same rate thus leaving the content of volume 1000 L at any time

Assume after entering constantly mixes and drains out.

Concentration flow = inflow – outflow

= 0.05(10) –

i.e. , Q(0) = 100

Use Q(0) = 5

-45 = A

So the equation would be

a) Initial concentratin =

b) Use the solution fo rDE substitute t =1

Q(1) = 50-45e^(-0.01) = 5.4477 kg

c) As t becomes large Q = 50

So concentration limit = 50/1000 = 0.05