## A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of $9.40 and a standard deviat Question A waitress believes the distribution of her tips has a model that is slightly skewed to the left, with a mean of$9.40 and a standard deviation of $6.10. She usually waits on about 60 parties over a weekend of work. a) Estimate the probability that she will earn at least$600

P(tips from 60 parties > $600) b) How much does she earn on the best 5% of such weekends? The total amount that she earns on the best 5% of such weekends is at least$__

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1 month 2021-10-18T13:31:35+00:00 1 Answer 0 views 0

## Answers ( )

a. P(tips from 60 parties > $600)=0.461 b. The total amount that she earns on the best 5% of such weekends is at least$19.43.

Step-by-step explanation:

a. To earn $600 in 60 parties means$10 per party in average.

If we assume a normal distribution of tips, we can calculate the z-value and its probability for this situation:

There is a probability of 46% that she earns at least $600 over a weekend of work. b. The best 5% of the weekends corresponds to: This probability (5%) corresponds to a z-value of z=1.6449. In tips, this value represents: The total amount that she earns on the best 5% of such weekends is at least$19.43.