a) What is the derivative of x^2 – 6x +36. b) Does this function have any maximum or minimum point?

Question

a) What is the derivative of x^2 – 6x +36.
b) Does this function have any maximum or minimum point?

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Delilah 4 weeks 2021-11-07T07:02:08+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-07T07:03:23+00:00

    Answer:

    2x - 6

    x=3 \rightarrow \ minimum \ point

    Step-by-step explanation:

    f(x) = x^2 - 6x +36

    The derivative is: f'(x)= 2x - 6

    To calculate the max/min point of the function, we use the first derivative and put it equal to zero (if needed)

    f'(x) = 2x - 6 = 0\\2x - 6 = 0\\2x = 6\\x = 3

    To check whether this point is max or min, we substitute the value of x in the second derivative of the function. If the answer is positive, the value is minimum. If the answer is negative, the value is minimum.

    f''(x) = 2

    The second derivative is positive, hence x = 3 is minimum.

    0
    2021-11-07T07:03:36+00:00

    Answer:

    2x-6

    Step-by-step explanation:

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45:7+7-4:2-5:5*4+35:2 =? ( )