A woman earns $ 1,350 in interest from two accounts in one year. If she has three times as much invested at 7% as she does at 6%, how much d

Question

A woman earns $ 1,350 in interest from two accounts in one year. If she has three times as much invested at 7% as she does at 6%, how much does she have in each account?​

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Camila 1 month 2021-10-18T13:13:26+00:00 1 Answer 0 views 0

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    2021-10-18T13:15:15+00:00

    Answer:

    The woman invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.

    Step-by-step explanation:

    We are given the following in the question:

    Let x be the interest earned from 7% interest rate and y be the interest earned from 6% interest rate.

    The woman invested has three times as much invested at 7% as she does at 6%.

    Thus, we can write the equation:

    x = 3y

    The total interest is $1,350.

    Thus, we can write the equation:

    1350 = \dfrac{7x}{100} + \dfrac{6y}{100}\\\\7x + 6y = 135000

    Solving the two equations by substitution method:

    7(3y) + 6y = 135000\\27y = 135000\\y = 5000\\x = 3(5000) = 15000

    Thus, she invested $15,000 at 7% interest rate and $5,000 at  6% interest rate.

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