A worker drives a 0.500 kg spike into a rail tie with a 2.50 kg sledgeham- mer. The hammer hits the spike with a speed of 65.0 m/s. If

Question

A worker drives a 0.500 kg spike into a rail tie with a 2.50 kg sledgeham-
mer. The hammer hits the spike with a speed of 65.0 m/s. If one-third of
the hammer’s kinetic energy is converted to the internal energy of the
hammer and spike, how much does the total internal energy increase?

in progress 0
Maya 1 week 2022-01-14T13:23:15+00:00 1 Answer 0 views 0

Answers ( )

    0
    2022-01-14T13:24:17+00:00

    Total internal energy increases by 1760 J

    Step-by-step explanation:

    The kinetic energy of an object is the energy possessed by the object due to its motion.

    It is calculated as

    KE=\frac{1}{2}mv^2

    where

    m is the mass of the object

    v is its speed

    For the hammer in this problem:

    m = 2.50 kg

    v = 65.0 m/s

    So its kinetic energy is

    KE=\frac{1}{2}(2.50)(65)^2=5281 J

    Then the problem says that 1/3 of the hammer’s kinetic energy is converted into internal energy: therefore, the total internal energy increases by

    \frac{1}{3}KE=\frac{1}{3}(5281)=1760 J

    Learn more about kinetic energy:

    brainly.com/question/6536722

    #LearnwithBrainly

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )