According to the Environmental Protection Agency (EPA), in a typical wetland environment, 36% of the water is outflow; 47% is seepage; 8% ev

Question

According to the Environmental Protection Agency (EPA), in a typical wetland environment, 36% of the water is outflow; 47% is seepage; 8% evaporates; and 9% remains as water volume in the ecosystem (Reference: United States Environmental Protection Agency Case Studies Report 832-R-93-005). Chloride compounds as residuals from residential areas are a problem for wetlands.
Suppose that in a particular wetland environment the following concentrations (mg/l) of chloride compounds were found:
outflow, 53.6; seepage, 73.9; remaining due to evaporation, 57.0; in the water volume, 74.0.
(a) Compute the weighted average of chlorine compound concentration (mg/l) for this ecological system. (Round your answer to one decimal place.)

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Piper 3 weeks 2021-12-28T22:38:44+00:00 1 Answer 0 views 0

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    2021-12-28T22:40:19+00:00

    Answer:

    A. 65.7 mg/l.

    B. iv. No. The average chlorine compound concentration (mg/l) is too high.

    Step-by-step explanation:

    Given:

    Outflow = 36%

    = 36 l in 100 l of wetland

    Seepage = 47%

    = 47 l in 100 l of wetland

    Evaporates = 8%

    = 8 l in 100 l of wetland

    Water volume = 9%

    = 36 l in 100 l of wetland

    Outflow = 53.6 mg/l

    Seepage = 73.9mg/l

    Remaining due to evaporation = 57.0mg/l

    Water volume = 74.0 mg/l

    Concentration of Chlorine compounds:

    Outflow = 36/100 * 53.6

    = 19.3 mg/l of outflow chlorine in the wetlands.

    Seepage = 47/100 * 73.9

    = 34.73 mg/l of seepage chlorine in the wetlands.

    Evaporates = 8/100 * 57

    = 4.56 mg/l of evaporates chlorine in the wetlands.

    Water volume = 9/100 * 74

    = 6.66 mg/l of outflow chlorine in the wetlands.

    Weighted average concentration of chlorine compounds in 100 l of wetland = total(X*W)/totalW

    Where,

    Total w = 0.36 + 0.47 + 0.08 + 0.09

    = 1

    Total X*W = 19.3 + 34.73 + 4.56 + 6.66

    = 65.65/1

    = 65.7 mg/l.

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45:7+7-4:2-5:5*4+35:2 =? ( )