An isosceles triangle has side that are 20,20 and 16. how long is the altitude of the triangle?

Question

An isosceles triangle has side that are 20,20 and 16. how long is the altitude of the triangle?

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Sarah 3 months 2021-10-20T20:20:01+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-20T20:21:02+00:00

    Answer:

    4\sqrt{21}

    Step-by-step explanation:

    16 is split into half to get 8. then use the pythagorean theorem to solve for the altitude.

    a^2 + b^2 = c^2

    8^2 + b^2 = 20^2

    64 + b^2 = 400

    b^2 = 336

    b = \sqrt{336}

    simplify to 4\sqrt{21}

    0
    2021-10-20T20:21:20+00:00

    Answer:18.3

    Step-by-step explanation:

    16/2=8

    altitude=√(20^2-8^2)

    altitude=√(20×20-8×8)

    altitude=√(400-64)

    altitude=√(336)

    altitude=18.3

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