An Olympic archer is able to hit the bull’s-eye 15% of the time. Assume each shot is independent of the others. If she shoots 7 arrows, what

Question

An Olympic archer is able to hit the bull’s-eye 15% of the time. Assume each shot is independent of the others. If she shoots 7 arrows, what’s the probability of each of the following results? a) Her first bull’s-eye comes on the third arrow. b) She misses the bull’s-eye at least once.c) Her first bull’s-eye comes on the fourth or fifth arrow.d) She gets exactly 4 bull’s-eyes.e) She gets at least 4 bull’s-eyes.f) She gets at most 4 bull’s-eyes.

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Kaylee 4 weeks 2021-11-06T15:23:20+00:00 1 Answer 0 views 0

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    2021-11-06T15:25:05+00:00

    Answer:

    a) 0.108

    b) 1.00

    c) 0.170

    d) 0.0109

    e) 0.0121

    f) 0.999

    Step-by-step explanation:

    Success: p = 0.15

    Failure: q = 1 – p = 0.85

    a) q²p = 0.85² × 0.15

    = 0.108375 = 0.108 (3 sf)

    b) 1 – P(all hits)

    = 1 – p⁷ = 1 – 0.15⁷

    = 0.9999982914= 1.00 (3 sf)

    c) q³p + q⁴p = 0.1704196875

    = 0.170 (3 sf)

    d) 7C4×p⁴×q³ = 35 × 0.15⁴ × 0.85³

    = 0.01088152734 = 0.0109 (3 sf)

    e) P(4,5,6 or 7)

    = 7C4×p⁴×q³ + 7C5×p⁵×q² +

    7C6×p⁶×q + 7C7×p⁷×q⁰

    = 0.01210317188 = 0.0121 (3 sf)

    f) 1 – P(more than 4)

    = 1-(0.01210317188-0.01088152734)

    = 1 – 0.001221644531

    = 0.9987783555 = 0.999 (3 sf)

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45:7+7-4:2-5:5*4+35:2 =? ( )