At 1:30 p.m., Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 miles per hour. Ten minutes later, Mary leaves

Question

At 1:30 p.m., Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 miles per hour. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour, when will she catch up with Tom

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Everleigh 3 weeks 2021-10-01T13:14:55+00:00 1 Answer 0

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    2021-10-01T13:16:12+00:00

    Answer: she would catch up with Tom in 1 hour.

    Step-by-step explanation:

    Let t represent the time it will take for Mary to catch up with Tom.

    Tom leaves his boat from a dock and travels at a rate of 25 miles per hour.

    Distance = speed × time

    Distance travelled by Tom in t hours is

    25 × t = 25t

    Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. Converting 10 minutes to hours, it becomes 10/60 hour

    Time spent by Mary is (t – 10/60) hours. If she travels at a rate of 30 miles per hour, it means that the distance that she would travel in

    (t – 10/60) hours is

    30(t – 10/60)

    = 30t – 5

    By the time she catches up with Tom, they would have covered the same distance. It means that

    25t = 30t – 5

    30t – 25t = 5

    5t = 5

    t = 5/5 = 1 hour

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