At a track meet 2/5 of the first place finishers went to Ohio State. One half of Ohio State’s first place finishers were women. If 2/9 of th

Question

At a track meet 2/5 of the first place finishers went to Ohio State. One half of Ohio State’s first place finishers were women. If 2/9 of the first place finishers who did NOT attend Ohio State were women, what fractional part of the total number of first place finishers were men?

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Kinsley 2 weeks 2021-09-11T02:41:28+00:00 1 Answer 0

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    2021-09-11T02:43:10+00:00

    Answer:

    2/3

    Step-by-step explanation:

    The first place finishers can be divided into two groups: those who went to Ohio State, and those who did not attend Ohio State.

    2/5 of the first place finishers went to Ohio State.  1/2 of these were women, which means 1/2 were men.  The fraction of first place finishers who went to Ohio State AND were men is:

    1/2 (2/5) = 1/5

    3/5 of the first place finishers did not attend Ohio State.  2/9 of these were women, which means 7/9 were men.  The fraction of first place finishers who did not attend Ohio State AND were men is:

    7/9 (3/5) = 7/15

    So the fraction of first place finishers who were men is:

    1/5 + 7/15

    = 3/15 + 7/15

    = 10/15

    = 2/3

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45:7+7-4:2-5:5*4+35:2 =? ( )