At Sally’s Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done b

Question

At Sally’s Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done by Amy. Chris finds that when he does hair cuts, 5% of the customers are not satisfied. Karine finds that when she does hair cuts, 6% of the customers are not satisfied. Amy finds that when she does hair cuts, 8% of the customers are not satisfied. Suppose that a customer leaving the salon is selected at random. If the customer is not satisfied, what is the probability that their hair was done by Amy

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Kennedy 2 weeks 2022-01-01T17:19:03+00:00 1 Answer 0 views 0

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    2022-01-01T17:20:30+00:00

    Answer:

    Probability that their hair was done by Amy is 0.475.

    Step-by-step explanation:

    We are given that Sally’s Hair Salon there are three hair stylists. 36% of the hair cuts are done by Chris, 26% are done by Karine, and the rest are done by Amy.

    Let the Probability of hair cutting done by Chris = P(C) = 0.36

    Probability of hair cutting done by Karine = P(K) = 0.26

    Probability of hair cutting done by Amy = P(A) = 0.368

    Also, let NS = event that customer is not satisfied with his cutting

    So, Probability that customers are not satisfied given that their hair cutting is done by Chris = P(NS/C) = 0.05

    Probability that customers are not satisfied given that their hair cutting is done by Karine = P(NS/K) = 0.06

    Probability that customers are not satisfied given that their hair cutting is done by Amy = P(NS/A) = 0.08

    Now, a customer leaving the salon is selected at random. If the customer is not satisfied, the probability that their hair was done by Amy is given by = P(A/NS)

    For finding the above probability we will use the concept of Bayes’ Theorem;

    SO, P(A/NS)  =  \frac{\text{P(A) \times P(NS/A)}}{\text{P(C) \times P(NS/C) + P(K) \times P(NS/K) +P(A) \times P(NS/A) }}[tex]\frac{P(A) \times P(NS/A) }{P(C) \times P(NS/C) +P(K) \times P(NS/K) +P(A) \times P(NS/A) }[/tex]

                         =  \frac{0.38 \times 0.08}{0.36 \times 0.05+0.26 \times 0.06+0.38 \times 0.08}

                         =  \frac{0.0304}{0.064}

                         =  0.475

    Hence, the probability that their hair was done by Amy is 0.475.

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