at the movie theatre, child admission is $5.20 and adult admission is $9.00. on Monday, 132 tickets were sold for a total sales of $994.20.

Question

at the movie theatre, child admission is $5.20 and adult admission is $9.00. on Monday, 132 tickets were sold for a total sales of $994.20. how many child tickets were sold that day?​

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Iris 2 weeks 2021-09-09T12:20:46+00:00 2 Answers 0

Answers ( )

    0
    2021-09-09T12:21:51+00:00

    Answer:

    That day 51 child tikets were sold

    Step-by-step explanation:

    To do this problem we have to make 2 equations, one that represents the number of entries and the other that represents the money

    x = child tickets

    y = adult tickets

    x + y = 132

    x * $5.20 + y * $9.00 = $994.20

    First we have to solve for the x in the first equation

    x + y = 132

    x = 132 – y

    Now we replace the x with (132 – y) in the second equation

    x * $5.20 + y * $9.00 = $994.20

    (132 – y) * 5.20 + y * 9.00 = 994.20

    686.4 – 5.2y + 9y = 994.2

    -5.2y + 9y = 994.2 – 686.4

    3.8y = 307.8

    y = 307.8/3.8

    y = 81

    We replace y with its value in the first equation

    x = 132 – y

    x = 132 – 81

    x = 51

    That day 51 child tikets were sold

    0
    2021-09-09T12:22:01+00:00

    Answer: 51 child tickets were sold that day.

    Step-by-step explanation:

    Let x represent the number of child admission tickets that were sold on Monday.

    Let y represent the number of child adult tickets that were sold on Monday.

    On Monday, 132 tickets were sold. It means that

    x + y = 132

    At the movie theatre, child admission is $5.20 and adult admission is $9.00. On Monday, the total sales was $994.20. This means that

    5.2x + 9y = 994.2- – – – – – – – – – – -1

    Substituting x = 132 – y into equation 1, it becomes

    5.2(132 – y) + 9y = 994.2

    686.4 – 5.2y + 9y = 994.2

    – 5.2y + 9y = 994.2 – 686.4

    3.8y = 307.8

    y = 307.8/3.8

    y = 81

    x = 132 – y = 132 – 81

    x = 51

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