## at the movie theatre, child admission is \$5.20 and adult admission is \$9.00. on Monday, 132 tickets were sold for a total sales of \$994.20.

Question

at the movie theatre, child admission is \$5.20 and adult admission is \$9.00. on Monday, 132 tickets were sold for a total sales of \$994.20. how many child tickets were sold that day?​

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2 weeks 2021-09-09T12:20:46+00:00 2 Answers 0

That day 51 child tikets were sold

Step-by-step explanation:

To do this problem we have to make 2 equations, one that represents the number of entries and the other that represents the money

x = child tickets

x + y = 132

x * \$5.20 + y * \$9.00 = \$994.20

First we have to solve for the x in the first equation

x + y = 132

x = 132 – y

Now we replace the x with (132 – y) in the second equation

x * \$5.20 + y * \$9.00 = \$994.20

(132 – y) * 5.20 + y * 9.00 = 994.20

686.4 – 5.2y + 9y = 994.2

-5.2y + 9y = 994.2 – 686.4

3.8y = 307.8

y = 307.8/3.8

y = 81

We replace y with its value in the first equation

x = 132 – y

x = 132 – 81

x = 51

That day 51 child tikets were sold

2. Answer: 51 child tickets were sold that day.

Step-by-step explanation:

Let x represent the number of child admission tickets that were sold on Monday.

Let y represent the number of child adult tickets that were sold on Monday.

On Monday, 132 tickets were sold. It means that

x + y = 132

At the movie theatre, child admission is \$5.20 and adult admission is \$9.00. On Monday, the total sales was \$994.20. This means that

5.2x + 9y = 994.2- – – – – – – – – – – -1

Substituting x = 132 – y into equation 1, it becomes

5.2(132 – y) + 9y = 994.2

686.4 – 5.2y + 9y = 994.2

– 5.2y + 9y = 994.2 – 686.4

3.8y = 307.8

y = 307.8/3.8

y = 81

x = 132 – y = 132 – 81

x = 51