At what points on the graph of f(x)=2x^3-6x^2-27x is the slope of the tangent line -9?

Question

At what points on the graph of f(x)=2x^3-6x^2-27x is the slope of the tangent line -9?

in progress 0
Adeline 2 months 2021-10-17T17:31:18+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-10-17T17:32:58+00:00

    Answer:

    (-1, 19) and (3, -81)

    Step-by-step explanation:

    f(x) = 2x³ − 6x² − 27x

    f'(x) = 6x² − 12x − 27

    -9 = 6x² − 12x − 27

    0 = 6x² − 12x − 18

    0 = x² − 2x − 3

    0 = (x + 1) (x − 3)

    x = -1 or 3

    f(-1) = 19

    f(3) = -81

    The points are (-1, 19) and (3, -81).

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )