Ben wants to try a new restaurant for dinner. His online search resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3<

Question

Ben wants to try a new restaurant for dinner. His online search
resulted in 7 new 3-star restaurants, 5 new 4-star restaurants, and 3
new 5-star restaurants. If he were to choose a restaurant at random,
what is the probability that he chooses a 5-star restaurant?
Select one:
33%
20%
47%
3%

in progress 0
Genesis 3 weeks 2021-10-08T02:11:21+00:00 2 Answers 0

Answers ( )

    0
    2021-10-08T02:12:51+00:00

    It would be about 3% I got this because you first had to multiply the results by the amount of stars they had so like 7*3 is 21 and so on if you did this to all the pairs you would get 56 now divide 56 by the amount of restaurants 7+5+3 which is 15 so 56 divided by 15 is about 3%

    0
    2021-10-08T02:13:13+00:00

    Ben found:
    7 ⭐️⭐️⭐️ restaurants
    5 ⭐️⭐️⭐️⭐️ restaurants
    3 ⭐️⭐️⭐️⭐️⭐️ restaurants
    A total of 15 restaurants

    Out of the 15 restaurants, 3 will be 5-star. So, 3/15, reduces to 1/5 and 1/5 as a percentage is 20%

    Ben’s probability of choosing a 5-star restaurant at random is 20%

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45:7+7-4:2-5:5*4+35:2 =? ( )