Choose the equation below whose axis of symmetry is x = 0. (1 point) Group of answer choices y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2

Question

Choose the equation below whose axis of symmetry is x = 0. (1 point) Group of answer choices y = x2 + 2x y = x2 − 16x + 58 y = x2 + 2 y = x2 − 4x + 2

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Josephine 3 weeks 2022-01-01T18:09:16+00:00 1 Answer 0 views 0

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    2022-01-01T18:10:44+00:00

    Answer:

    (C)y = x^2 +2

    Step-by-step explanation:

    Given the general form of quadratic equation ax^2+bc+c=0, the axis of symmetry is derived using the equation x=-\frac{b}{2a}

    Given the equation

    y = x^2 + 2x\\a=1, b=2\\Axis of Symmetry, x=-\frac{2}{2(1)}=-1

    Next,

    y = x^2 -16x+58\\a=1, b=-16\\$Axis of Symmetry$, x=-\frac{-16}{2(1)}=8

    Next,

    y = x^2 +2\\a=1, b=0\\$Axis of Symmetry$, x=-\frac{0}{2(1)}=0

    Lastly,

    y = x^2 -4x+2\\a=1, b=-4\\$Axis of Symmetry$, x=-\frac{-4}{2(1)}=2

    Clearly, y = x^2 +2 is the equation whose axis of symmetry is x=0.

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45:7+7-4:2-5:5*4+35:2 =? ( )