Complex numbers are used in electronics to describe the current in an electric circuit. Ohm’s law relates the current in a circuit, I, in am

Question

Complex numbers are used in electronics to describe the current in an electric circuit. Ohm’s law relates the current in a circuit, I, in amperes, the voltage of the circuit, E, in volts, and the resistance of the circuit, R, in ohms, by the formula E- IR. Solve the problem using this formula. Find E, the voltage of a circuit, if I (16 +) amperes and R=2+4) ohms (32 +66i volte.

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Maya 4 weeks 2021-12-29T05:06:15+00:00 1 Answer 0 views 0

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    2021-12-29T05:08:07+00:00

    Answer:

    E = 3072i – 5904ohms

    Step-by-step explanation:

    From ohms law recalled that E = IR given already

    E = voltage (volts)

    I = Current (amps)

    R = resistance (ohms)

    Therefore, by substitution

    I = 16i and R = (2+4)ohms(32+66i)

    = 6(32+66i) ohms

    = (192+396i)ohms

    E = (16i)×(192+396i)

    E = 3072i + 5904i²

    Recall that i² = -1 from complex number

    E = 3072i +5904(-1)

    E = 3072i – 5904ohms

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45:7+7-4:2-5:5*4+35:2 =? ( )