## Consider a data set containing the following values: 80, 94, 93, 106, 91, 90, 96, 99 The mean of the preceding values is 93.625. The deviati

Question

Consider a data set containing the following values: 80, 94, 93, 106, 91, 90, 96, 99 The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows: –13.625, 0.375, –0.625, 12.375, –2.625, –3.625, 2.375, 5.375 (a) If this is sample data, the sample variance is ___ and the sample standard deviation is ___. (b) If this is population data, the population variance is ___ and the population standard deviation is ___. (c) Suppose the smallest value of 80 in the data was misrecorded as 8. If you were to recalculate the variance and standard deviation with the 8 instead of the 80, your new values for the variance and standard deviation would be ___ and ___.

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1 week 2021-11-21T15:54:58+00:00 1 Answer 0 views 0

a) And if we replace we got: And the sample deviation is just the square root of the variance: b) And if we replace we got: And the deviation would be: c) 8, 94, 93, 106, 91, 90, 96, 99

For this case the new mean would be: The new sample variance would be: And the new deviation would be: Step-by-step explanation:

For this case we have the following data given:

80, 94, 93, 106, 91, 90, 96, 99

The mean calculated from the following formula is: And the deviations from the mean of the data are:

–13.625, 0.375, –0.625, 12.375, –2.625, –3.625, 2.375, 5.375

Part a

The sample variance is given by the following formula: And if we replace we got: And the sample deviation is just the square root of the variance: Part b

Is the data given comes from a population data then the variance is calculaded as: And if we replace we got: And the deviation would be: Part c

For this case we have this new data:

8, 94, 93, 106, 91, 90, 96, 99

For this case the new mean would be: The new sample variance would be: And the new deviation would be: 