Consider a game in which a player rolls one die. If an odd number comes​ up, the player wins the number of dollars showing on the die. If an

Question

Consider a game in which a player rolls one die. If an odd number comes​ up, the player wins the number of dollars showing on the die. If an even number comes​ up, the player loses the number of dollars showing on the die. Calculate the expected value for this game. Is the game​ fair? (Assume that there is no cost to play the​ game.)

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Serenity 1 day 2021-09-14T02:37:33+00:00 1 Answer 0

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    2021-09-14T02:39:11+00:00

    The die has six sides.

    Three are of an even (loosing) number: 2, 4, 6

    Three of an an odd (winning) number:  1, 3, 5

    The even numbers are greater.

    The average even (loosing) number is 4.

    The average odd (winning) number is 3.

    On average, you can expect to loose half-a-dollar.

    (If you want a math equation)

    E=(1/6)(1)+(1/6)(-2)+(1/6)(3)+(1/6)(-4)+(1/6)(5)+1/6(-6)

    E=(1/6) (1-2+3-4+5-6)=-3/6=-1/2

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45:7+7-4:2-5:5*4+35:2 =? ( )